q5

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q5

by bacali » Sat Nov 29, 2008 10:15 pm
oa: C
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by parallel_chase » Sat Nov 29, 2008 11:05 pm
angles inside the quardilateral can be

180 -x
180 -y
180 -z
180 -w


4 sides, sum of the interior angles = (n-2)*180 = (4-2)*180 = 360

180 -x + 180 -y + 180 -z + 180 -w = 360

x+y+z+w = 720-360 = 360

From the above equation you can clearly see how C can be the answer.

Hope this helps.
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Justification of C

by agoyal2 » Sat Nov 29, 2008 11:17 pm
Image

Extending both the lines to form a triangle,
(180-w)+(180-z)+a=180.

Also, From the smaller triangle, a+x+y = 180
=>x+y = 180-a => w+z (Substituting from above)

So, we need both w and z to find out x+y, hence C