DS Practice test question #10
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DS Practice test question
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are you sure the series of questions you just posted are not discussed earlier?
Do use search feature & kindly add keywords in the title of the thread so that it'd help other members search /seek your thread in future
Do use search feature & kindly add keywords in the title of the thread so that it'd help other members search /seek your thread in future
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I think the answer should be C.
lxl = y-z ?
Statement I
x+y=z
x=z-y
-x=y-z
Insufficient.
Statement II
x<0
we dont know anything about y and z.
Insufficient.
Combining I & II
x<0
-x=y-z
lxl=y-z
hence sufficient.
lxl = y-z ?
Statement I
x+y=z
x=z-y
-x=y-z
Insufficient.
Statement II
x<0
we dont know anything about y and z.
Insufficient.
Combining I & II
x<0
-x=y-z
lxl=y-z
hence sufficient.
- ashish1354
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if we deduce -x=y-z
from 1 then it is sufficient to say that y-z is not =lxl
please suggest if i am wrong
so answer is A[/list]
from 1 then it is sufficient to say that y-z is not =lxl
please suggest if i am wrong
so answer is A[/list]
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Even if x is greater than 0, |x| should lead to the same value in case of -x or +x.
Please correct me if I am wrong. Answer should be A
Please correct me if I am wrong. Answer should be A
From the stem: x=y-z if x is positive; x= z-y or x+y=z if negative
Stmt 1: x+y = z
But it is unknown whether x is positive or negative - INSUFF
Stmt 2:
x is negative -INSUFF
Stmts 1& 2, x+y=z, and x is neg - SUFF
Answer should be C.
What is OA???
Stmt 1: x+y = z
But it is unknown whether x is positive or negative - INSUFF
Stmt 2:
x is negative -INSUFF
Stmts 1& 2, x+y=z, and x is neg - SUFF
Answer should be C.
What is OA???
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Might as well throw my two cents in...
I think it's A.
1. x+y=z
You can manipulate the first statement to get:
x= z-y
multiplying both sides by -1 we get:
-x=y-z
The opposite of x is the same thing as the absolute value of x, so 1 is sufficient.
2. x<0
Doesn't tell us anything. we can pick any numbers or x, y or z. Insufficient.
so, IMO A
I think it's A.
1. x+y=z
You can manipulate the first statement to get:
x= z-y
multiplying both sides by -1 we get:
-x=y-z
The opposite of x is the same thing as the absolute value of x, so 1 is sufficient.
2. x<0
Doesn't tell us anything. we can pick any numbers or x, y or z. Insufficient.
so, IMO A
I think that's not the case.ashish1354 wrote:if we deduce -x=y-z
from 1 then it is sufficient to say that y-z is not =lxl
please suggest if i am wrong
so answer is A[/list]
It depends whether x >= 0 or not.
If X >= 0, then |x| = x
If X<0, then |x| = -x
therefore, if x < o, then -x = y-z is equal to |x| = y-z
but if x>= 0, then -x = y-z is NOT equal to |x| = y-z which is equal to x=y-z
but since we don't know, whether x>=0 or X<0, we can't completely say that statement I solves the problem
I think you are misunderstanding with answer "No" to a question is also an answer ....concept.
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The correct answer is (C).
The problem with statement (1) is that we don't know the signs. Let's pick numbers to illustrate.
Does |x| = y - z
Before looking at the statements, let's note that |x| is never negative. So, if z > y, there's no way the two sides can be equal.
(1) x = z - y
Well, we could pick:
x = -3
z = 2
y = 5
(-3 = 2 - 5)
Plugging in:
Does |-3| = 5 - 2? YES
We could also pick:
x = 3
z = 5
y = 2
(3 = 5 - 2)
Does |3| = 2 - 5? NO
Since we can get both a yes and a no answer, (1) is insufficient.
However, if we know that x is negative (statement (2)), then we know from statement (1) that y > z and that the two sides WILL be equal.
Separately the statements are insufficient, together sufficient: choose (C).
The problem with statement (1) is that we don't know the signs. Let's pick numbers to illustrate.
Does |x| = y - z
Before looking at the statements, let's note that |x| is never negative. So, if z > y, there's no way the two sides can be equal.
(1) x = z - y
Well, we could pick:
x = -3
z = 2
y = 5
(-3 = 2 - 5)
Plugging in:
Does |-3| = 5 - 2? YES
We could also pick:
x = 3
z = 5
y = 2
(3 = 5 - 2)
Does |3| = 2 - 5? NO
Since we can get both a yes and a no answer, (1) is insufficient.
However, if we know that x is negative (statement (2)), then we know from statement (1) that y > z and that the two sides WILL be equal.
Separately the statements are insufficient, together sufficient: choose (C).
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