If x and y are non-zero integers and |x| + |y| = 32, what is xy?
(1) -4x – 12y = 0
(2) |x| – |y| = 16
Lets have discussions first
Sorry for posting the Q on PS..my bad.
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Absolut
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jimmiejaz
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IMO ans is A.
given |x| + |y| = 32
and from 1 we have x=-3y
putting we get
|-3y| + |y| = 32
|y|=8
x=-24 if y=8 or x=24 if y=-8
In both cases xy=24*(-8) or (-24)*8
Hence suff.
From 2 we have |x|-|y| = 16
solving we get
|x| = 24, |y| = 8
x,y can be both negative and positive so for both xy will change.
Hence insuff.
But i want to know if the values of x and y can be negative for these two equations as taken by me for statement 2, or in other words if the OA is D
given |x| + |y| = 32
and from 1 we have x=-3y
putting we get
|-3y| + |y| = 32
|y|=8
x=-24 if y=8 or x=24 if y=-8
In both cases xy=24*(-8) or (-24)*8
Hence suff.
From 2 we have |x|-|y| = 16
solving we get
|x| = 24, |y| = 8
x,y can be both negative and positive so for both xy will change.
Hence insuff.
But i want to know if the values of x and y can be negative for these two equations as taken by me for statement 2, or in other words if the OA is D
What if i have not yet beat the beast, I know i will beat it!!!!!!!!
