0-10 X
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Stmt II
z=5x
x=1 z=5
x+10/2>z
If x=2 then x+10/2<z
INSUFF
Stmt I
Take x any value for z to be closer to 10 z has to be always greater than x+10/2
SUFF
There could be other approaches but this is mine!!!
A)
z=5x
x=1 z=5
x+10/2>z
If x=2 then x+10/2<z
INSUFF
Stmt I
Take x any value for z to be closer to 10 z has to be always greater than x+10/2
SUFF
There could be other approaches but this is mine!!!
A)
- logitech
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0........x........[(10+x)/2]...........10
If Z sits in the middle it means that it is the average of 10 and X but since Z is closer to the 10 it means that Z is greater than the average of 10 and X - SUF
If Z sits in the middle it means that it is the average of 10 and X but since Z is closer to the 10 it means that Z is greater than the average of 10 and X - SUF
LGTCH
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Thanks cramya, logitech.
I have a question:
How much time did u take to complete it. Mine was around 3 mins
Any quick shortcuts??
thanks
I have a question:
How much time did u take to complete it. Mine was around 3 mins
Any quick shortcuts??
thanks
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I don't see how statement 1 is sufficient.
If z is 9 and x is 8, then we have...
9>(8+10)/2?
9>9?
no....
Did I miss something?
If z is 9 and x is 8, then we have...
9>(8+10)/2?
9>9?
no....
Did I miss something?
- Stuart@KaplanGMAT
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Except that if z is 9 and x is 8, then z is NOT closer to 10 than it is to x!EricLien9122 wrote:I don't see how statement 1 is sufficient.
If z is 9 and x is 8, then we have...
9>(8+10)/2?
9>9?
no....
Did I miss something?
We're only allowed to use numbers that fit the statements provided. Your values of x=8 and z=9 violate statement (1), so they're invalid.
By definition, the average of two numbers is right in the middle of the two numbers on the number line. So, if z is closer to the big number than the small number, z will definitely be greater than the average.
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