What is the value of X?
1. x^2+y^2=25
2. xy=12
OA E
Where Am I wrong?
x=12/y -------> (12/y)^2+y^2=25
144/y^2+y^2=25 --------> (y^4+144)/y^2=25 ------> y^4+144-25y^2=0
Sqrt [y^4+144-25y^2=0] --------> y^2-5y+12=0
Then the solution should be C
Value of X
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Fine till herecartera wrote:What is the value of X?
1. x^2+y^2=25
2. xy=12
OA E
Where Am I wrong?
x=12/y -------> (12/y)^2+y^2=25
144/y^2+y^2=25 --------> (y^4+144)/y^2=25 ------> y^4+144-25y^2=0
But you can't do the following
If you want to solve the equation y^4+144-25y^2=0cartera wrote: Sqrt [y^4+144-25y^2=0] --------> y^2-5y+12=0
Then the solution should be C
substitute y^2 = z
you'll get z^2 -25z +144 = 0
solve for z
plug z into the equation y^2 = z
and then solve for x by using the equation xy=12
OR
when you had xy=12
you could've substituted for y i.e. y = 12/x and then the whole equation would've been in terms of x and not y
hope this helps..