positive/negative
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- Maciek
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Hi!
IMO E
x^2*y > 0 ?
x^2*y > 0 if y > 0 and (x < 0 or x > 0 )
(1) y^2 > 0
Therefore, y < 0 or y > 0
Statement (1) ALONE is INSUFFICIENT
(2) x = 2
Statement (2) ALONE is INSUFFICIENT
Statements (1) & (2) BOTH are together INSUFFICIENT.
Hope it helps!
Best,
Maciek
IMO E
x^2*y > 0 ?
x^2*y > 0 if y > 0 and (x < 0 or x > 0 )
(1) y^2 > 0
Therefore, y < 0 or y > 0
Statement (1) ALONE is INSUFFICIENT
(2) x = 2
Statement (2) ALONE is INSUFFICIENT
Statements (1) & (2) BOTH are together INSUFFICIENT.
Hope it helps!
Best,
Maciek
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- sumit.sinha
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- Gurpinder
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I assumed something silly.
I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.
I misapplied this here!
I see why (E) is the right answer.
Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y
Thx.
I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.
I misapplied this here!
I see why (E) is the right answer.
Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y
Thx.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.
- sumit.sinha
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It is function question.Gurpinder wrote:I assumed something silly.
I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.
I misapplied this here!
I see why (E) is the right answer.
Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y
Thx.
it says x*y is defined as x^2*y.
i.e. if x=2 and y=3 then 2*3 value will be 2^2*3 = 12 even tough 2*3 (in real world)=6.
Cheers,
Sumit
Sumit
- Gurpinder
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Oh man. I need some Coffee.sumit.sinha wrote:It is function question.Gurpinder wrote:I assumed something silly.
I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.
I misapplied this here!
I see why (E) is the right answer.
Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y
Thx.
it says x*y is defined as x^2*y.
i.e. if x=2 and y=3 then 2*3 value will be 2^2*3 = 12 even tough 2*3 (in real world)=6.
Thx Sumit.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.
- sumit.sinha
- Senior | Next Rank: 100 Posts
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Yeah they look a little awkward first time around.Gurpinder wrote:Oh man. I need some Coffee.sumit.sinha wrote:It is function question.Gurpinder wrote:I assumed something silly.
I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.
I misapplied this here!
I see why (E) is the right answer.
Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y
Thx.
it says x*y is defined as x^2*y.
i.e. if x=2 and y=3 then 2*3 value will be 2^2*3 = 12 even tough 2*3 (in real world)=6.
Thx Sumit.
Hey, why is your target score 900+ . i think the exam is out of 800. lol
Cheers,
Sumit
Sumit
- Gurpinder
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lol.... just having fun =)sumit.sinha wrote:Yeah they look a little awkward first time around.Gurpinder wrote:Oh man. I need some Coffee.sumit.sinha wrote:It is function question.Gurpinder wrote:I assumed something silly.
I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.
I misapplied this here!
I see why (E) is the right answer.
Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y
Thx.
it says x*y is defined as x^2*y.
i.e. if x=2 and y=3 then 2*3 value will be 2^2*3 = 12 even tough 2*3 (in real world)=6.
Thx Sumit.
Hey, why is your target score 900+ . i think the exam is out of 800. lol
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.