if -2x > 3y ,is x negative?
1. y>0
2. 2x+5y-20=0
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Hi,
-2x>3y
From(1):y>0. So -2x which is greater than 3y is also greater than 0
So, x is negative.
Sufficient
From(2): -2x = 5y-20
As -2x>3y, 5y-20>3y =>y>10. As y is positive, x should be negative
Sufficient
Hence, D
-2x>3y
From(1):y>0. So -2x which is greater than 3y is also greater than 0
So, x is negative.
Sufficient
From(2): -2x = 5y-20
As -2x>3y, 5y-20>3y =>y>10. As y is positive, x should be negative
Sufficient
Hence, D
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1) y>0;prithviforever wrote:if -2x > 3y ,is x negative?
1. y>0
2. 2x+5y-20=0
multiplying 3 on both sides we have;
3y>0;
for -2x to become greater than 3y; x must be negative; because positive quantity is always greater than negative quantity, hence x must be negative, hence 1 alone is sufficient to answer the question.
2) 2x+5y=20;
also -2x>3y can be written as; 3y+2x<0;
2x+3y=20-2y;
now since 3y+2x<0; i.e. left hand side is negative therefore rhs must also be negative;
i.e. 20-2y<0;
20<2y;
10<y;since y>10; i.e. y is positive and greater than 10, therefore inequality will hold true only if x is negative,, hence 2 alone is also sufficient to answer this question..!!!
hence answer should be D
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a)y>0 thus 3y>0if -2x > 3y ,is x negative?
1. y>0
2. 2x+5y-20=0
also -2x>3y>0
thus x<0
Sufficient
b)2x+3y<0
y<-2x/3
5y<-10x/3
2x+5y-20<-4x/3-20
4x/3 + 20 <0
x<-15
Sufficient
IMO D
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Statement 1: y > 0prithviforever wrote:if -2x > 3y ,is x negative?
1. y>0
2. 2x+5y-20=0
Hence, 3y > 0 --> -2x > 0 --> x < 0
Sufficient
Statement 2: 2x + 5y - 20 = 0
Hence, y = (20 - 2x)/5
Now, -2x > 3y --> -2x > 3*(20 - 2x)/5
--> -10x > 60 - 6x
--> 4x < -60
--> x < -15
Sufficient
The correct answer is D.
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