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Linear problem
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clock60
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one possible way to solve is to adopt the problem to smth old onedkumar.83 wrote:
say scale S=axis x and x1=30, x2=60 (on x-y plane)
R scale =axis y y1=6, and y2=24
find the slope=(y2-y1)/(x2-x1)=(24-6)/(60-30)=3/5
function is linea 3/5=(y-24)/(100-60)=48, where y corresponds to the measurement on R scale
i got 48-C
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gmatmachoman
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Linear equation is of the form
y= m*x + C
Let Y belong to R scale & X belong to S scale
6= m*30 +C ----eq 1
24= m*60 +C ----eq 2
solve for m & C
we get m=3/5 & c= -12
Substitute these values in the "required " eqn as:
R scale : m* S +C
: 3/5 *100 +(-12)
:60-12
:48
Solved!!
y= m*x + C
Let Y belong to R scale & X belong to S scale
6= m*30 +C ----eq 1
24= m*60 +C ----eq 2
solve for m & C
we get m=3/5 & c= -12
Substitute these values in the "required " eqn as:
R scale : m* S +C
: 3/5 *100 +(-12)
:60-12
:48
Solved!!
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Stuart@KaplanGMAT
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- Location: Toronto
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Hi!
Here's an explanation from an older post (a search of "r scale" found the old thread).
https://www.beatthegmat.com/pls-help-t12930.html
Here's an explanation from an older post (a search of "r scale" found the old thread).
https://www.beatthegmat.com/pls-help-t12930.html
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
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