For a nonnegative integer n, if the remainder is 1 when 2n is divided by 3, then which of
the following must be true?
I. n is greater than zero.
II. 3n = (-3)n
III. √2n is an integer.
A. I only
B. II only
C. I and II
D. I and III
E. II and III
Hi guys i got its answer as D.Is it correct?
Non Negative Integer
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rapper wrote:For a nonnegative integer n, if the remainder is 1 when 2n is divided by 3, then which of
the following must be true?
I. n is greater than zero.
II. 3n = (-3)n
III. √2n is an integer.
A. I only
B. II only
C. I and II
D. I and III
E. II and III
Hi guys i got its answer as D.Is it correct?
Here we first see the multiples of 3 are 3,6,9,12,15,18,21,24.....so on
multiples of 2 are 2,4,6,8,10,12,14,16,18,20,22,24,26
We observe when the multiples of 2 are a perfect square like 4, 16, then the remainder is 1 when divided by 3 also , the third condition i.e √2n is an integer holds true.
√4= 2(integer)
√16=4(integer)
√64=8(integer)
Hence I and III condition hold true.
Answer is D
- anuprajan5
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I would go with A on this one.
Because for option 3, it could be true in some cases and not true as well. Example - 10, 14 etc..
Because for option 3, it could be true in some cases and not true as well. Example - 10, 14 etc..
Regards
Anup
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Anup
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Yes you guys are right, seems like i missed some cases here. In fact this is called a blunder!
answer seems A here.
answer seems A here.