A. 8

B. 10

C. 11

D. 12

E. 15

The OA is B

**Source: e-GMAT**

00:00

**A**

**B**

**C**

**D**

**E**

A solution contains water, milk and liquid chocolate in the ratio of 2:3:5 by volume. If y liters of water and milk each are added to this solution, the resultant solution would contain 25 percent of water by volume. If the volume of this resultant solution is 120 liters, what is the value of y in liters?

A. 8

B. 10

C. 11

D. 12

E. 15

The OA is B

**Source: e-GMAT**

A. 8

B. 10

C. 11

D. 12

E. 15

The OA is B

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**Posts:**3008**Joined:**22 Aug 2016**Location:**Grand Central / New York**Thanked**: 470 times**Followed by:**32 members

Say initially, the solution had 2x, 3x, and 5x liters of water, milk and liquid chocolate, respectively.swerve wrote: ↑Mon Jun 29, 2020 12:31 pmA solution contains water, milk and liquid chocolate in the ratio of 2:3:5 by volume. If y liters of water and milk each are added to this solution, the resultant solution would contain 25 percent of water by volume. If the volume of this resultant solution is 120 liters, what is the value of y in liters?

A. 8

B. 10

C. 11

D. 12

E. 15

The OA is B

Source: e-GMAT

After the addition of y liters of water and milk each, the solution now has (2x + y), (3x + y), and 5x liters of water, milk and liquid chocolate, respectively. And the total content of the solution is (2x + y) + (3x + y) + 5x = (10x + 2y) liters

=> 10x + 2y = 120 => 5x + y = 60 ---(1)

Water in the new solution = 25% of 120 = 30 ltrs

=> 2x + y = 30 ---(2)

Solving (1) and (2), we get x = y = 10.

Correct answer: B

Hope this helps!

-Jay

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swerve wrote: ↑Mon Jun 29, 2020 12:31 pmA solution contains water, milk and liquid chocolate in the ratio of 2:3:5 by volume. If y liters of water and milk each are added to this solution, the resultant solution would contain 25 percent of water by volume. If the volume of this resultant solution is 120 liters, what is the value of y in liters?

A. 8

B. 10

C. 11

D. 12

E. 15

The OA is B

We can let the amount of water, milk, and liquid chocolate in the original solution be 2x, 3x, and 5x (where x is a positive number). We can create the equations:

2x + 3x + 5x + y + y = 120

and

(2x + y)/(2x + 3x + 5x + y + y) = 1/4

Simplifying the first equation, we have:

10x + 2y = 120

5x + y = 60

y = 60 - 5x

Substituting this in the second equation (and noticing that the denominator is just 120), we have:

(2x + 60 - 5x)/120 = 1/4

60 - 3x = 30

30 = 3x

10 = x

Since y = 60 - 5x, y = 60 - 5(10) = 10.

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