A certain mixture is made up of compounds \(A, B,\) and \(C.\) Compound B accounts for \(70\) percent of the mixture. How many more liters of compound A must be added so that the mixture is \(25\) percent compound \(A?\)
1) If \(3\) times more compound \(A\) than is currently in the mixture were added, the mixture would be \(50\) percent compound \(A\)
2) If half of the compound \(B\) were removed from the mixture, there would be \(175\) liters of compound \(B\)
The OA is C
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Mixture Problems
by
swerve » Wed Aug 07, 2024 4:42 pm
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