In the quadrilateral PQRS, side PS is parallel to side QR. Is PQRS a parallelogram?
(1) PS = QR
(2) PQ = RS
OA is A but I think it should be D.
If we know that PS || QR then if PQ = RS shouldn't PQ || RS also? I've tried to sketch it to get it to be wrong but I can't come up with any situation where it doesn't make a parallelogram.
MGMAT - parallelogram
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Its hard to explain without a diagram.
PS ll QR
Obviously you see that A is sufficient
I will try a diagram this way, not sure how it will turn out
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As you can see the two parellel lines (PS and QR) can produce two lines of equal length that are not parellel. Hence, it is not a parellogram.
That is only possible if PQ not equal PS. If they are equal, only a parrellogram is possible.
IMO A
PS ll QR
Obviously you see that A is sufficient
I will try a diagram this way, not sure how it will turn out
-----------------------------
- -
- -
_-_______________________________-
As you can see the two parellel lines (PS and QR) can produce two lines of equal length that are not parellel. Hence, it is not a parellogram.
That is only possible if PQ not equal PS. If they are equal, only a parrellogram is possible.
IMO A
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Thanks for trying. I think I finally was able to envision what it would look likemike22629 wrote:Lol didnt turn out well.
To explain it:
Imagine two 45/45/90 triangles on opposite sides of a square facing the opposite direction. That was the shape I was trying to illustrate.
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