## MGMAT - abs problem

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### MGMAT - abs problem

by jayhawk2001 » Sun May 13, 2007 2:51 pm
OA coming after few reply

What is the value of y?

(1) 3|x^2 – 4| = y – 2

(2) |3 – y| = 11

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by mendiratta » Sun May 13, 2007 11:23 pm
1. Itself can't answer because we don't know x.
2. y=14 or -8 , so insufficient.

but from 1, we get y = 3|x^2 - 4 | + 2
which means 3 * (something positive) + 2, is positive.
So y = 14.

is it C?

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by gabriel » Mon May 14, 2007 11:23 am
...C for me too ...

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by isisalaska » Mon May 14, 2007 11:31 am
E perhpas...if y could be -8 or 14, how can you find out what is the value of "y" in you plug it in statement 1?

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by jayhawk2001 » Mon May 14, 2007 6:58 pm
isisalaska wrote:E perhpas...if y could be -8 or 14, how can you find out what is the value of "y" in you plug it in statement 1?
OA is C.

Isis, using (1), you can see that y is positive (please see mendiratta's
post). So, using 1 and 2, we can converge on y = 14.

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