The lifetime of all the batteries produced by a certain company in a year have a distribution that is symmetric about the mean m. If the distribution has a standard deviation of d, what percentage of the distribution is greater than m+d?
1) 68% of the distribution lies in the interval from m-d to m+d inclusive.
2) 16% of the distribution is less than m-d.
Mean and standard deviation
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Stmt1)
68% lies between m-d and m+d, which means the other 32% lies outside that area.
since the disutrubution is symmetric about the mean, this 32% will be equally divided between less than m-d and more than m+d
thus, % more than m+d = 32/2 = 16%
Sufficient
Stmt2)
If 16% is less than m-d, then 16% is also greater than m+d, since the distribution is symmetric.
sufficient
IMO, (D). OA please?
68% lies between m-d and m+d, which means the other 32% lies outside that area.
since the disutrubution is symmetric about the mean, this 32% will be equally divided between less than m-d and more than m+d
thus, % more than m+d = 32/2 = 16%
Sufficient
Stmt2)
If 16% is less than m-d, then 16% is also greater than m+d, since the distribution is symmetric.
sufficient
IMO, (D). OA please?
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