The GMAT Avengers Challenge of the Week: Inequalities – Part 1:

by on September 26th, 2016

Happy Monday!

In order to score a high Quant score, you need to know how to tackle Inequalities. Make sure you join Rahul and the rest of the Avengers group on Saturday, October 1 at 11:30am EST as they share tips and strategies to help you beat the GMAT with 700+.

In the meantime, here’s this week’s challenge problem for you to solve:

Is b < 0?

(1) Integer b is a multiple of 13

(2) b^3 < 13

A) Statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not.

B) Statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not.

C) Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient.

D) EITHER statement BY ITSELF is sufficient to answer the question.

E) Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, requiring more data pertaining to the problem.

Let us know the answer in the comments section below! We will reveal the answer during the live Facebook session on Saturday. Make sure you RSVP now!

7 comments

  • answer is option C which says combining statement 1 and 2 will be sufficient answer .

    • E. Could be 0 or any -ve multiple of 13

  • I think its A because every factor or multiple is positive, and since the least multiple of 13 is 0, therefore 0 is not less than 0. 

    • A multiple can be negative or positive, for example 26 is a multiple of 13 (13*2) but so is -26 (13*-2). A is not sufficient.

      B is not suffiecent on it's own because b^3 could be any negative number OR positive 1 or 2.

      Together, the statements are sufficient because for statement 2 to be true, the only positive numbers that work are 1 or 2; however, neither of those satisfy statement 1 and are a multiple of 13. However, -13, -26 or any other negative multiple of 13 satisfies statement 2 as well, so the answer is C - together they are sufficient.

  • C as positive multiples of 13 cube will never satisfy option 2... Only a -vet number will.

  • I go with option E as it could be any -ve multiple of 13 also..1 & 2 gives you either positive or negative multiple of 13 which could be less than 13 or cubes of positive or negative numbers less than 13

  • Ignore option C is the answer

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