profit and loss

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profit and loss

by sgr21 » Wed Jun 04, 2014 1:56 am
The profit earned when an article is sold for $ 600 is double the loss incurred when the article is sold for $150. At what price should the article be sold if a profit of 20% is to be earned?

(A)$150
(B) $300
(C) $360
(D)$400
(E) $450

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by sanju09 » Wed Jun 04, 2014 2:21 am
sgr21 wrote:The profit earned when an article is sold for $ 600 is double the loss incurred when the article is sold for $150. At what price should the article be sold if a profit of 20% is to be earned?

(A)$150
(B) $300
(C) $360
(D)$400
(E) $450
Let's start trying plugging in the answers, starting from [spoiler](C)[/spoiler] as usual:

[spoiler](C)[/spoiler] If the article should be sold at $360 to earn a profit of 20%, then the real cost of the article must be 5/6($360) = $300, which if sold at $600 earns a profit of $300, which is double of the loss ($150) if the same is sold at $150. Thus, [spoiler](C)[/spoiler] perfectly works and hence the answer.
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by theCodeToGMAT » Wed Jun 04, 2014 2:47 am
Longer approach :)

Price = X

Profit = 600 - x

Loss = X - 150

(600 - x) = 2 * (X - 150)
900 = 3x
x = 300

Profit = 20% ==> 300* 1.2 = 360
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by sanju09 » Wed Jun 04, 2014 9:48 pm
theCodeToGMAT wrote:Longer approach :)

Price = X

Profit = 600 - x

Loss = X - 150

(600 - x) = 2 * (X - 150)
900 = 3x
x = 300

Profit = 20% ==> 300* 1.2 = 360
[spoiler]Hmm...maze le rahe ho?[/spoiler]

How's that longer, buddy?
The mind is everything. What you think you become. -Lord Buddha



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Quantitative Instructor
The Princeton Review - Manya Abroad
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by theCodeToGMAT » Wed Jun 04, 2014 11:51 pm
sanju09 wrote:
theCodeToGMAT wrote:Longer approach :)

Price = X

Profit = 600 - x

Loss = X - 150

(600 - x) = 2 * (X - 150)
900 = 3x
x = 300

Profit = 20% ==> 300* 1.2 = 360
[spoiler]Hmm...maze le rahe ho?[/spoiler]

How's that longer, buddy?
haha... I meant that my method is longer than your's. :)
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