Is \(a > |b|?\)

This topic has expert replies
Moderator
Posts: 7187
Joined: Thu Sep 07, 2017 4:43 pm
Followed by:23 members

Is \(a > |b|?\)

by BTGmoderatorDC » Wed May 22, 2019 3:22 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Is \(a > |b|?\)

(1) \(2^{a-b} > 16\)
(2) \(|a - b| < b\)


OA C

Source: e-GMAT

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 2095
Joined: Tue Dec 04, 2012 3:22 pm
Thanked: 1443 times
Followed by:247 members

by ceilidh.erickson » Sat May 25, 2019 12:05 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Is \(a > |b|?\)
Since this question contains an absolute value, we must be sure to think about NEGATIVE as well as positive possibilities.
(1) \(2^{a-b} > 16\)
First, get like bases:
\(2^{a-b}>2^4\)

We can infer:
\(a-b>4\)
\(a>b+4\)

Since a is greater than b+4, it must also be greater than b itself. But be careful! That doesn't mean a>|b|.

Think of examples where a and b are both negative:
a = -1
b = -6
This satisfies \(a>b+4\) but not \(a > |b|\)
(2) \(|a - b| < b\)
This tells us that b must be positive, because it's greater than some absolute value. But this could be true whether a is greater than or less than b:
a = 3
b = 2
|3 - 2| < 2
\(a > |b|?\) --> yes

a = 2
b = 3
|2 - 3| < 3
\(a > |b|?\) --> no

This is insufficient.

(1) and (2) together

If \(a>b+4\) and \(b>0\), then a must be a positive number greater than b. Thus, the answer to \(a > |b|?\) is yes.

The answer is C.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 2095
Joined: Tue Dec 04, 2012 3:22 pm
Thanked: 1443 times
Followed by:247 members

by ceilidh.erickson » Sat May 25, 2019 12:10 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education