Is 8^x > 4^y?

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Is 8^x > 4^y?

by BTGModeratorVI » Sat Aug 08, 2020 7:09 am

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Is 8^x > 4^y?

1) x > y
2) 3x > 2y

Answer: B
Source: Math Revolution

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Re: Is 8^x > 4^y?

by Brent@GMATPrepNow » Mon Aug 10, 2020 4:49 am

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BTGModeratorVI wrote:
Sat Aug 08, 2020 7:09 am
Is 8^x > 4^y?

1) x > y
2) 3x > 2y

Answer: B
Source: Math Revolution
Target question: Is 8^x > 4^y?

This is a great candidate for rephrasing the target question.
Aside: We have a free video with tips on rephrasing the target question: https://www.gmatprepnow.com/module/gmat- ... cy?id=1100

Notice that we can rewrite 8 and 4 with the same BASE to get: Is (2³)^x > (2²)^y?
Now apply the power of a power law to get: Is 2^3x > 2^2y?
Since 2^2y is always positive, we can safely divide both sides by 2^2y to get: Is (2^3x)/(2^2y) > 1?
Simplify to get: Is 2^(3x - 2y) > 1?
For 2^(3x -2y) to be greater than 1, the exponent, 3x - 2y, must be greater than 0.
So, we get:
REPHRASED target question: Is 3x - 2y > 0?

At this point, the question can be handled quickly

Statement 1: x > y
Can we use this information to answer the REPHRASED target question?
No.
There are several values of x and y that satisfy statement 1. Here are two:
Case a: x = 2 and y = 1. In this case 3x - 2y = 3(2) - 2(1) = 4. In other words, 3x - 2y > 0
Case b: x = -3 and y = -4. In this case 3x - 2y = 3(-3) - 2(-4) = -1. In other words, 3x - 2y < 0
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: 3x > 2y
Subtract 2y from both sides to get 3x - 2y > 0
PERFECT!!
This means we can answer the REPHRASED target question with certainty. So, statement 2 is SUFFICIENT

Answer: B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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