how i can tell which kind of circle this is and how do i find the area cause my answer is 1
so how did they get root 3/2
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inscribed or circumscribed
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coolgirl26
- Senior | Next Rank: 100 Posts
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- Joined: Tue Mar 03, 2009 1:24 pm
angle ABC = 90 degrees (angle subtending a diameter)
AB^2 + BC^2 = AC^2
AC = 2, BC = 1 -> AB^2 + 1 = 4
AB^2 = 3
AB = root(3)
Area of triangle = 1/2 x base x (perpendicular) height
= 1/2 x BC x AB
= 1/2 x 1 x root(3)
= root(3)/2
B.
AB^2 + BC^2 = AC^2
AC = 2, BC = 1 -> AB^2 + 1 = 4
AB^2 = 3
AB = root(3)
Area of triangle = 1/2 x base x (perpendicular) height
= 1/2 x BC x AB
= 1/2 x 1 x root(3)
= root(3)/2
B.
-
coolgirl26
- Senior | Next Rank: 100 Posts
- Posts: 71
- Joined: Tue Mar 03, 2009 1:24 pm
