If x and y are positive, is 4x > 3y?
(1) x > y - x
(2) x/y < 1
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inequalities
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goelmohit2002
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sumitkhurana
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IMO E.
We need to find if x > .75y
1) x > .5y -- But we don't know if it is greater than .75 y, insufficient.
2) x < y. But we don't know how less -- insufficient.
1 + 2.
.5y < x < y -- insufficient.
Answer E.
We need to find if x > .75y
1) x > .5y -- But we don't know if it is greater than .75 y, insufficient.
2) x < y. But we don't know how less -- insufficient.
1 + 2.
.5y < x < y -- insufficient.
Answer E.
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sanjay_dce
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from stmt1 2x>y or 4x>2y ( we dont know whether 4x>3y)beater wrote:If x and y are positive, is 4x > 3y?
(1) x > y - x
(2) x/y < 1
from stmt2 since x and y ar +ve its safe to multiply y on both sides of inequality hence we know x<y or -x>-y
using both 1 and 2
we know that 3x>y ( still we dont know if 4x > 3y)
hence no doubt the ans is E
is 4x-3y>0?
I. x>y-x
= 2x>y
= 4x>2y
2y-3y>0
-y >0
or
y < 0
but in the question stem it is given y is postive
Insufficient
II. x/y < 1
x<y
if x = 1, y = 3, then 4x-3y is negative
if x = 1/4, y = 1/3, then 4x-3y = 0
Insufficient
I and II taken together are insufficient
Hence E
I. x>y-x
= 2x>y
= 4x>2y
2y-3y>0
-y >0
or
y < 0
but in the question stem it is given y is postive
Insufficient
II. x/y < 1
x<y
if x = 1, y = 3, then 4x-3y is negative
if x = 1/4, y = 1/3, then 4x-3y = 0
Insufficient
I and II taken together are insufficient
Hence E
SACX
