Is AD > BC?

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Is AD > BC?

by BTGmoderatorDC » Thu Sep 30, 2021 6:13 pm

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Screenshot 2020-04-01 at 8.41.48 PM.png
Is AD > BC?

(1) CD = AB
(2) Angle CAB = Angle BCA


OA A

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Re: Is AD > BC?

by rk_gmat » Fri Oct 01, 2021 11:17 am

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B

C

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Given:
Angles,
ADC = 90\({^0}\)
ABC = 90\({^0}\)
To find:
AD > BC ?

1) CD=AB
Therefore, it becomes a rectangle => AD = BC

SUFFICIENT

2) Angle, CAB = BCA
=> Triangle ABC is 45-90-45
=> \(AC\ =\sqrt{2}BC\ =\ \sqrt{2}\ AB\)
=> AD < \(\sqrt{BC}\)
but can't say AD < BC or not clearly

NOT SUFFICIENT

Choice: A