## In the figure above $$- \angle ABC = \angle ADC = 90^{\circ}.$$ Is $$AD > BC?$$

##### This topic has expert replies
Moderator
Posts: 1894
Joined: 29 Oct 2017
Thanked: 1 times
Followed by:5 members

### In the figure above $$- \angle ABC = \angle ADC = 90^{\circ}.$$ Is $$AD > BC?$$

by M7MBA » Sun Aug 15, 2021 3:22 pm

00:00

A

B

C

D

E

## Global Stats

In the figure above $$- \angle ABC = \angle ADC = 90^{\circ}.$$ Is $$AD > BC?$$

(1) $$\angle CAB = \angle BCA$$
(2) $$CD > AB$$