In sequence of 9 distinct numbers {a1,a2,a3................a9}, nth term is given by an = an−1 + b, where 2 ≤ n ≤ 9 and b is a constant. How many of the terms in the sequence are negative?
(1) a1 = 16
(2) a5 = 0
OA B
Source: e-GMAT
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In sequence of 9 distinct numbers
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BTGmoderatorDC
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Jay@ManhattanReview
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Let's take each statement one by one.BTGmoderatorDC wrote: ↑Fri Feb 07, 2020 5:15 pmIn sequence of 9 distinct numbers {a1,a2,a3................a9}, nth term is given by an = an−1 + b, where 2 ≤ n ≤ 9 and b is a constant. How many of the terms in the sequence are negative?
(1) a1 = 16
(2) a5 = 0
OA B
Source: e-GMAT
(1) a1 = 16
Since we do not have any information about b, we cannot calculate the values of the terms. Insufficient.
(2) a5 = 0
Since a5 = 0, there are two possibilities:
(a) a1, a2, a3, and a4 are negative and a6, a7, a8, and a9 are positive. Thus, there are 4 negative terms.
(b) a1, a2, a3, and a4 are positive and a6, a7, a8, and a9 are negative. Thus, there are 4 negative terms.
In either case, the answer is 4. Sufficient.
The correct answer: B
Hope this helps!
-Jay
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