In a certain sequence, the term $A_n$ is given by the formula $A_n=16-\dfrac{(4-n)^3}{|n-4|}$ for all positive

Manhattan Prep

In a certain sequence, the term $A_n$ is given by the formula $A_n=16-\dfrac{(4-n)^3}{|n-4|}$ for all positive integers $n \neq 4,$ while $A_4=16.$ For which integer value of k greater than 2 is the mean of all values in the sequence from $A_1$ through $A_k$ equal to the median of those values?

A. 6
B. 7
C. 8
D. 9
E. 10

OA B

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