If the product of the integers w, x, y and z is 770, and if

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If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?

A. 10
B. 13
C. 16
D. 18
E. 21



OA B

Source: Official Guide

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by SampathKp » Sun Dec 29, 2019 7:23 pm
BTGmoderatorDC wrote:If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?

A. 10
B. 13
C. 16
D. 18
E. 21



OA B

Source: Official Guide
Prime factors of 770 are 2*5*7*11
So 1<2<5<7<11

So of w+z = 2+11 = 13

Answer is B

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by Brent@GMATPrepNow » Mon Dec 30, 2019 6:54 am
BTGmoderatorDC wrote:If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?

A. 10
B. 13
C. 16
D. 18
E. 21
This looks like a job for prime factorization!

770 = (2)(5)(7)(11)

If 1 < w < x < y < z, then we can see that w = 2, x = 5, y = 7 and z = 11

So, w + z = 2 + 11 = 13

Answer: B

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by Scott@TargetTestPrep » Sun Jan 05, 2020 8:06 pm
BTGmoderatorDC wrote:If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?

A. 10
B. 13
C. 16
D. 18
E. 21



OA B

Source: Official Guide
Since 770 = 2 * 5 * 7 * 11, then w = 2, x = 5, y = 7 and z = 11. Therefore, the sum of w and z is 2 + 11 = 13.

Answer: B

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