If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
OA B
Source: Official Guide
If the product of the integers w, x, y and z is 770, and if
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Prime factors of 770 are 2*5*7*11BTGmoderatorDC wrote:If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
OA B
Source: Official Guide
So 1<2<5<7<11
So of w+z = 2+11 = 13
Answer is B
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This looks like a job for prime factorization!BTGmoderatorDC wrote:If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
770 = (2)(5)(7)(11)
If 1 < w < x < y < z, then we can see that w = 2, x = 5, y = 7 and z = 11
So, w + z = 2 + 11 = 13
Answer: B
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Brent
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Since 770 = 2 * 5 * 7 * 11, then w = 2, x = 5, y = 7 and z = 11. Therefore, the sum of w and z is 2 + 11 = 13.BTGmoderatorDC wrote:If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
OA B
Source: Official Guide
Answer: B
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