Jack bought five mobiles at an average price of $150. The

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Jack bought five mobiles at an average price of $150. The median of all the prices is $200. What is the minimum possible price of the most expensive mobile that Jack has bought, if the price of the most expensive mobile is at least thrice that of the least expensive mobile?

A. $150
B. $200
C. $250
D. $300
E. $350

OA B.

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by regor60 » Thu Sep 13, 2018 6:09 am
AAPL wrote:e-GMAT

Jack bought five mobiles at an average price of $150. The median of all the prices is $200. What is the minimum possible price of the most expensive mobile that Jack has bought, if the price of the most expensive mobile is at least thrice that of the least expensive mobile?

A. $150
B. $200
C. $250
D. $300
E. $350

OA B.
Five mobiles @ $150 average price means $750 spent

The middle phone cost $200 and there are two phones that cost that amount or more and two that cost that amount or less.

Therefore, the minimum price that the most expensive phone could cost without constraint is then $200, so that eliminates A. Let's assume $200 is the most expensive phone and see if the constraint of most expensive being minimum 3x least cost phone can be met

If the most expensive phone cost $200, then so did the next most costly since the median also cost $200. So that's $600 of the $750 spent, leaving $150 for the last two phones.

The least cost phone costs no more than $200/3 or $66 2/3, leaving $150 - $66 2/3 = $83 1/3 as the cost of the next phone.

So, given that the $83 1/3 is greater than $66 2/3, the proper order is preserved and the constraint is met, answer B, 200

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by Brent@GMATPrepNow » Thu Sep 13, 2018 6:21 am
AAPL wrote:e-GMAT

Jack bought five mobiles at an average price of $150. The median of all the prices is $200. What is the minimum possible price of the most expensive mobile that Jack has bought, if the price of the most expensive mobile is at least thrice that of the least expensive mobile?

A. $150
B. $200
C. $250
D. $300
E. $350

OA B.
Jack bought five mobiles at an average price of $150.
So, (sum of all 5 mobiles)/5 = $150
Multiply both sides by 5 to get: sum of all 5 mobiles = $750

The median of all the prices is $200.
Let a = smallest value
Let b = 2nd smallest value
Let d = largest value
Let c = 2nd largest value
So, when we arrange the values in ASCENDING order we get: a, b, $200, c, d

From here, a quick approach is to test each answer choice, starting from the smallest value

A) $150
This answer choice suggests that d = $150, which is impossible, since the greatest value cannot be less than the median ($200)
ELIMINATE A

B) $200
This answer choice suggests that d = $200
Let's add this to our list to get: a, b, $200, c, $200
This means c must also equal $200. So we have: a, b, $200, $200, $200

Is it possible to assign values to a and b so that all of the conditions are met?
YES!
We must satisfy the condition that sum of all 5 mobiles = $750 and it must be the case that the price of the most expensive mobile is at least thrice that of the least expensive mobile
Well, if we let a = $50, then the price of the most expensive mobile ($200) is at least thrice that of the least expensive mobile ($50)
Finally, if we let b = $100, we get: $50, $100, $200, $200, $200, which meets the condition that sum of all 5 mobiles = $750
PERFECT!!

Answer: B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Scott@TargetTestPrep » Wed Apr 10, 2019 4:56 pm
AAPL wrote:e-GMAT

Jack bought five mobiles at an average price of $150. The median of all the prices is $200. What is the minimum possible price of the most expensive mobile that Jack has bought, if the price of the most expensive mobile is at least thrice that of the least expensive mobile?

A. $150
B. $200
C. $250
D. $300
E. $350

OA B.

We are looking for the minimum possible price of the most expensive mobile. Notice that the total price of the 5 mobiles is 150 x 5 = $750, and the median price is $200, Let's now analyze the given answer choices.

Since the price of the most expensive mobile must be at least the median price, we can eliminate choice A. So let's start with choice B.

B. $200

If the price of the most expensive mobile is $200, then each of 3 most expensive mobiles is $200. So the total price of the 2 least expensive mobile is 750 - 3 x 200 = $150. We can have the least expensive mobile as $50 and the second least expensive mobile as $100. So the price of the most expensive mobile is 4 times (which is at least 3 times) the price of the least expensive mobile. This satisfies the given parameters of the problem. So the correct answer is B.

Answer: B

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