If the average (arithmetic mean) of the 4 numbers n + 2, 2n - 3, 4n + 1, and 7n + 4 is 15, what is the value of n?
A. 11/4
B. 4
C. 32/7
D. 11
E. 13
OA B
Source: GMAT Prep
If the average (arithmetic mean) of the 4 numbers n + 2, 2n - 3, 4n + 1, and 7n + 4 is 15, what is the value of n?
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Since the average (arithmetic mean) of the 4 numbers n + 2, 2n - 3, 4n + 1, and 7n + 4 is 15, we haveBTGmoderatorDC wrote: ↑Thu Jan 23, 2020 5:18 pmIf the average (arithmetic mean) of the 4 numbers n + 2, 2n - 3, 4n + 1, and 7n + 4 is 15, what is the value of n?
A. 11/4
B. 4
C. 32/7
D. 11
E. 13
OA B
Source: GMAT Prep
[(n + 2) + (2n - 3) + (4n + 1) + (7n + 4)]/4 = 15
=> 14n + 4 = 60 => n = 4.
The correct answer: B
Hope this helps!
-Jay
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Average = sum/numberBTGmoderatorDC wrote: ↑Thu Jan 23, 2020 5:18 pmIf the average (arithmetic mean) of the 4 numbers n + 2, 2n - 3, 4n + 1, and 7n + 4 is 15, what is the value of n?
A. 11/4
B. 4
C. 32/7
D. 11
E. 13
OA B
Source: GMAT Prep
sum=n+2+2n-3+4n+1+7n+4=14n+4
Average=14n+4/4
given Average=14
14=14n+4/4
n=4
Therefore, __B__
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We can use the average formula:BTGmoderatorDC wrote: ↑Thu Jan 23, 2020 5:18 pmIf the average (arithmetic mean) of the 4 numbers n + 2, 2n - 3, 4n + 1, and 7n + 4 is 15, what is the value of n?
A. 11/4
B. 4
C. 32/7
D. 11
E. 13
OA B
Source: GMAT Prep
average = sum/quantity
15 = [(n + 2) +(2n – 3) + (4n + 1) + (7n + 4)] / 4
15 = (14n + 4)/4
60 = 14n + 4
56 = 14n
4 = n
Answer: B
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