If Teena is driving at 55 miles per hour and is currently 7.5 miles behind Joe, who is driving at 40 miles per hour in the same direction then in how many minutes will Teena be 15 miles ahead of Joe?
A. 15
B. 60
C. 75
D. 90
E. 105
OA D
Source: Princeton Review
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If Teena is driving at 55 miles per hour and is currently 7.5 miles behind Joe, who is driving at 40 miles per hour in
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BTGmoderatorDC
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Total distanceTeena has to drive \(= 7.5 + 15 =22.5\) milesBTGmoderatorDC wrote: ↑Mon Feb 22, 2021 4:51 pmIf Teena is driving at 55 miles per hour and is currently 7.5 miles behind Joe, who is driving at 40 miles per hour in the same direction then in how many minutes will Teena be 15 miles ahead of Joe?
A. 15
B. 60
C. 75
D. 90
E. 105
OA D
Source: Princeton Review
relative speed \(=55-40=15\) miles per hour
Time taken by her to reach \(15\) miles ahead of Joe \(= \dfrac{22.5}{15}=\dfrac{3}{2}=1.5\) hours \(=90\) minutes
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Solution:BTGmoderatorDC wrote: ↑Mon Feb 22, 2021 4:51 pmIf Teena is driving at 55 miles per hour and is currently 7.5 miles behind Joe, who is driving at 40 miles per hour in the same direction then in how many minutes will Teena be 15 miles ahead of Joe?
A. 15
B. 60
C. 75
D. 90
E. 105
OA D
In order for Teena to go from 7.5 miles behind Joe to 15 miles ahead of him, she must travel 7.5 + 15 = 22.5 miles more than Joe. Therefore, we can create the equation when t is the number of hours it takes Teena to accomplish that feat:
40t + 22.5 = 55t
22.5 = 15t
1.5 = t
We see that it takes 1.5 hours or 90 minutes for Teena to go from 7.5 miles behind Joe to 15 miles ahead of him.
Answer: D
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