If quadrilateral ABCD, pictured above, has a perimeter of 64
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from 1, the length of diagonal is same. So the quadrilateral is either square or rectangle. But we cant figure out what is it. So, not sufficient.
From 2, diagonals are perpendicular to each other. So, the quadrilateral is either square or rhombus.
So, side = 64/4= 16
In square or rhombus, diagonals bisect each other and are perpendicular to each other.
Using Pythagoras Theorem, we can find out the length of the diagonal.
Hence sufficient.
Hence B
From 2, diagonals are perpendicular to each other. So, the quadrilateral is either square or rhombus.
So, side = 64/4= 16
In square or rhombus, diagonals bisect each other and are perpendicular to each other.
Using Pythagoras Theorem, we can find out the length of the diagonal.
Hence sufficient.
Hence B