Manhattan Prep
If none of the students are ambidextrous, what percentage of the 20 students in Mr. Henderson's class are lefthanded?
1) Of the 12 girls in the class, 25% are lefthanded
2) 5 of the boys in the class are righthanded
OA C
If none of the students are ambidextrous, what percentage of the 20 stundents in Mr. Henderson's class are lefthanded?
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Target question => what percentage of the 20 students in Mr. Henderson's class are lefthanded?
Total students = 20
Statement 1: Of the 12 girls in the class, 25% are lefthanded.
Total girls = 12; lefthanded girls = 25% * 12 = 3
Righthanded girls = 12  3 = 9
Total boys = 20  12 = 8
However, the number of lefthanded boys is unknown. Therefore, statement is NOT SUFFICIENT.
Statement 2: 5 of the boys in the class are righthanded.
There is no information about lefthanded boys and girls. So, statement 2 is NOT SUFFICIENT.
Combining both statements together:
From statement 1:
Total girls = 12; lefthanded girls = 3
Righthanded girls = 9
Total boys = 8
From statement 2:
Righthanded boys = 5
Lefthanded boys = 8  5 = 2
Total lefthanded students = 3 + 3 = 6
% of students who are lefthanded = (6/20) * 100 = 30%
Both statements combined together ARE SUFFICIENT.
Answer = option C
Total students = 20
Statement 1: Of the 12 girls in the class, 25% are lefthanded.
Total girls = 12; lefthanded girls = 25% * 12 = 3
Righthanded girls = 12  3 = 9
Total boys = 20  12 = 8
However, the number of lefthanded boys is unknown. Therefore, statement is NOT SUFFICIENT.
Statement 2: 5 of the boys in the class are righthanded.
There is no information about lefthanded boys and girls. So, statement 2 is NOT SUFFICIENT.
Combining both statements together:
From statement 1:
Total girls = 12; lefthanded girls = 3
Righthanded girls = 9
Total boys = 8
From statement 2:
Righthanded boys = 5
Lefthanded boys = 8  5 = 2
Total lefthanded students = 3 + 3 = 6
% of students who are lefthanded = (6/20) * 100 = 30%
Both statements combined together ARE SUFFICIENT.
Answer = option C