If $m$ has the smallest prime number as its only prime factor, is $(\sqrt{m})^3$ an integer?

If $m$ has the smallest prime number as its only prime factor, is $(\sqrt{m})^3$ an integer?

(1) $m^2$ is divisible by $32.$

(2) $\sqrt{m}$ is divisible by $4.$

Answer: E

Source: e-GMAT

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