If a, b, and c are integers and abc ≠0, is a2 - b2 a multiple of 4?
(1) a = (c - 1)^2
(2) b = c2 - 1
Answer= C
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I have a question on this problem. If you were to multiply out statement 1, you would get:
a = (c-1)^2
a = (c-1)(c-1)
a = c^2 -2c + 1
So, if you were to plug that in for a in the original equation, you would get:
a^2 - b^2
(a+b)(a-b)
((c^2 -2c + 1) + b)((c^2 -2c + 1) -b)
So, without solving that equation, wouldn't you know that the term has to be divisible by 4 given that the middle term -2c is in there twice so 2c * 2c is 4c^2?
I am probably making the wrong assumption but I feel like that was enough information for me.
[DS]If a, b, and c are integers and abc ≠0
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Thanks for the reply. I guess I understand the principle but is their a way of testing those different outcomes without picking numbers and trying each possibility to see if it fits the rules?srcc25anu wrote:See image attached for detailed calculations.
Ans C
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Sure, the middle term might be divisible by 4, but we cannot conclude that the entire expression is divisible by 4. For example, 20 is divisible by 4, but 1 + 20 + 3 is not divisible by 4.acchi369 wrote:
a^2 - b^2
(a+b)(a-b)
((c^2 -2c + 1) + b)((c^2 -2c + 1) -b)
So, without solving that equation, wouldn't you know that the term has to be divisible by 4 given that the middle term -2c is in there twice so 2c * 2c is 4c^2?
Cheers,
Brent
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NOTE: I added some exponent signs (^) to the question to avoid any confusion.acchi369 wrote:If a, b, and c are integers and abc ≠0, is a^2 - b^2 a multiple of 4?
(1) a = (c - 1)^2
(2) b = c^2 - 1
Target question: Is a^2 - b^2 a multiple of 4?
Since a^2 - b^2 = (a + b)(a - b), we can rephrase the target question . . .
Rephrased target question: Is (a + b)(a - b) a multiple of 4?
Statement 1: a = (c - 1)^2
This tells us a little bit about the properties of a, but we know nothing about b. So, there is no way to determine whether or not (a + b)(a - b) is a multiple of 4.
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: b = c^2 - 1
This tells us a little bit about the properties of b, but we know nothing about a. So, there is no way to determine whether or not (a + b)(a - b) is a multiple of 4.
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined:
Statement 1 tells us that a = (c - 1)^2
Expand to get: a = c^2 - 2c + 1
Statement 2 tells us that b = c^2 - 1
No we can replace a and b with their respective values:
(a + b)(a - b) = [(c^2 - 2c + 1) + (c^2 - 1)] [(c^2 - 2c + 1) - (c^2 - 1)]
= [2c^2 - 2c][-2c + 2]
= [2(c^2 - c)][2(-c + 1)] I factored the 2 out of each set of brackets
= 4(c^2 - c)(-c + 1)
At this point, we can see that (a + b)(a - b) is definitely a multiple of 4.
Since we can answer the target question with certainty, the combined statements are SUFFICIENT
Answer = C
Cheers,
Brent
Last edited by Brent@GMATPrepNow on Thu Jul 11, 2013 6:45 am, edited 1 time in total.
- faraz_jeddah
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Hi Brent. Typo in your solution. S1 and S2 independently are INsufficient.Brent@GMATPrepNow wrote:NOTE: I added some exponent signs (^) to the question to avoid any confusion.acchi369 wrote:If a, b, and c are integers and abc ≠0, is a^2 - b^2 a multiple of 4?
(1) a = (c - 1)^2
(2) b = c^2 - 1
Target question: Is a^2 - b^2 a multiple of 4?
Since a^2 - b^2 = (a + b)(a - b), we can rephrase the target question . . .
Rephrased target question: Is (a + b)(a - b) a multiple of 4?
Statement 1: a = (c - 1)^2
This tells us a little bit about the properties of a, but we know nothing about b. So, there is no way to determine whether or not (a + b)(a - b) is a multiple of 4.
Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: b = c^2 - 1
This tells us a little bit about the properties of b, but we know nothing about a. So, there is no way to determine whether or not (a + b)(a - b) is a multiple of 4.
Since we can answer the target question with certainty, statement 2 is SUFFICIENT
Statements 1 and 2 combined:
Statement 1 tells us that a = (c - 1)^2
Expand to get: a = c^2 - 2c + 1
Statement 2 tells us that b = c^2 - 1
No we can replace a and b with their respective values:
(a + b)(a - b) = [(c^2 - 2c + 1) + (c^2 - 1)] [(c^2 - 2c + 1) - (c^2 - 1)]
= [2c^2 - 2c][-2c + 2]
= [2(c^2 - c)][2(-c + 1)] I factored the 2 out of each set of brackets
= 4(c^2 - c)(-c + 1)
At this point, we can see that (a + b)(a - b) is definitely a multiple of 4.
Since we can answer the target question with certainty, the combined statements are SUFFICIENT
Answer = C
Cheers,
Brent
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Thanks for catching that, faraz.faraz_jeddah wrote: Hi Brent. Typo in your solution. S1 and S2 independently are INsufficient.
I've edited my response.
Cheers,
Brent