[DS]If a, b, and c are integers and abc ≠ 0

This topic has expert replies
Junior | Next Rank: 30 Posts
Posts: 13
Joined: Sat Jun 30, 2012 4:05 pm
Thanked: 1 times
If a, b, and c are integers and abc ≠ 0, is a2 - b2 a multiple of 4?

(1) a = (c - 1)^2

(2) b = c2 - 1

Answer= C

******
Potential spoiler below
******
******


I have a question on this problem. If you were to multiply out statement 1, you would get:

a = (c-1)^2
a = (c-1)(c-1)
a = c^2 -2c + 1

So, if you were to plug that in for a in the original equation, you would get:

a^2 - b^2
(a+b)(a-b)
((c^2 -2c + 1) + b)((c^2 -2c + 1) -b)

So, without solving that equation, wouldn't you know that the term has to be divisible by 4 given that the middle term -2c is in there twice so 2c * 2c is 4c^2?

I am probably making the wrong assumption but I feel like that was enough information for me.

Master | Next Rank: 500 Posts
Posts: 423
Joined: Fri Jun 11, 2010 7:59 am
Location: Seattle, WA
Thanked: 86 times
Followed by:2 members

by srcc25anu » Mon Jul 01, 2013 6:57 pm
See image attached for detailed calculations.

Ans C
Attachments
abc.JPG

Junior | Next Rank: 30 Posts
Posts: 13
Joined: Sat Jun 30, 2012 4:05 pm
Thanked: 1 times

by acchi369 » Tue Jul 02, 2013 6:23 pm
srcc25anu wrote:See image attached for detailed calculations.

Ans C
Thanks for the reply. I guess I understand the principle but is their a way of testing those different outcomes without picking numbers and trying each possibility to see if it fits the rules?

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Wed Jul 03, 2013 5:53 am
acchi369 wrote:
a^2 - b^2
(a+b)(a-b)
((c^2 -2c + 1) + b)((c^2 -2c + 1) -b)

So, without solving that equation, wouldn't you know that the term has to be divisible by 4 given that the middle term -2c is in there twice so 2c * 2c is 4c^2?
Sure, the middle term might be divisible by 4, but we cannot conclude that the entire expression is divisible by 4. For example, 20 is divisible by 4, but 1 + 20 + 3 is not divisible by 4.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Wed Jul 03, 2013 6:12 am
acchi369 wrote:If a, b, and c are integers and abc ≠ 0, is a^2 - b^2 a multiple of 4?

(1) a = (c - 1)^2

(2) b = c^2 - 1

NOTE: I added some exponent signs (^) to the question to avoid any confusion.

Target question: Is a^2 - b^2 a multiple of 4?

Since a^2 - b^2 = (a + b)(a - b), we can rephrase the target question . . .

Rephrased target question: Is (a + b)(a - b) a multiple of 4?

Statement 1: a = (c - 1)^2
This tells us a little bit about the properties of a, but we know nothing about b. So, there is no way to determine whether or not (a + b)(a - b) is a multiple of 4.
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: b = c^2 - 1
This tells us a little bit about the properties of b, but we know nothing about a. So, there is no way to determine whether or not (a + b)(a - b) is a multiple of 4.
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined:
Statement 1 tells us that a = (c - 1)^2
Expand to get: a = c^2 - 2c + 1

Statement 2 tells us that b = c^2 - 1

No we can replace a and b with their respective values:
(a + b)(a - b) = [(c^2 - 2c + 1) + (c^2 - 1)] [(c^2 - 2c + 1) - (c^2 - 1)]
= [2c^2 - 2c][-2c + 2]
= [2(c^2 - c)][2(-c + 1)] I factored the 2 out of each set of brackets
= 4(c^2 - c)(-c + 1)
At this point, we can see that (a + b)(a - b) is definitely a multiple of 4.
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C


Cheers,
Brent
Last edited by Brent@GMATPrepNow on Thu Jul 11, 2013 6:45 am, edited 1 time in total.
Brent Hanneson - Creator of GMATPrepNow.com
Image

User avatar
Master | Next Rank: 500 Posts
Posts: 358
Joined: Thu Apr 18, 2013 9:46 am
Location: Jeddah, Saudi Arabia
Thanked: 42 times
Followed by:7 members
GMAT Score:730

by faraz_jeddah » Thu Jul 11, 2013 12:24 am
Brent@GMATPrepNow wrote:
acchi369 wrote:If a, b, and c are integers and abc ≠ 0, is a^2 - b^2 a multiple of 4?

(1) a = (c - 1)^2

(2) b = c^2 - 1

NOTE: I added some exponent signs (^) to the question to avoid any confusion.

Target question: Is a^2 - b^2 a multiple of 4?

Since a^2 - b^2 = (a + b)(a - b), we can rephrase the target question . . .

Rephrased target question: Is (a + b)(a - b) a multiple of 4?

Statement 1: a = (c - 1)^2
This tells us a little bit about the properties of a, but we know nothing about b. So, there is no way to determine whether or not (a + b)(a - b) is a multiple of 4.
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: b = c^2 - 1
This tells us a little bit about the properties of b, but we know nothing about a. So, there is no way to determine whether or not (a + b)(a - b) is a multiple of 4.
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Statements 1 and 2 combined:
Statement 1 tells us that a = (c - 1)^2
Expand to get: a = c^2 - 2c + 1

Statement 2 tells us that b = c^2 - 1

No we can replace a and b with their respective values:
(a + b)(a - b) = [(c^2 - 2c + 1) + (c^2 - 1)] [(c^2 - 2c + 1) - (c^2 - 1)]
= [2c^2 - 2c][-2c + 2]
= [2(c^2 - c)][2(-c + 1)] I factored the 2 out of each set of brackets
= 4(c^2 - c)(-c + 1)
At this point, we can see that (a + b)(a - b) is definitely a multiple of 4.
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C


Cheers,
Brent
Hi Brent. Typo in your solution. S1 and S2 independently are INsufficient. :)

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Thu Jul 11, 2013 6:46 am
faraz_jeddah wrote: Hi Brent. Typo in your solution. S1 and S2 independently are INsufficient. :)
Thanks for catching that, faraz.
I've edited my response.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image