Source: Manhattan Prep
If a and b are constants, what is one solution of the equation \((x+a)(x-b)=0?\)
1) \(a = 4\)
2) \(b = 3\)
The OA is D
If a and b are constants, what is one solution of the equation (x + a)(x – b) = 0?
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Target question: What is one solution of the equation (x + a)(x - b) = 0BTGmoderatorLU wrote: ↑Wed Dec 08, 2021 9:50 amSource: Manhattan Prep
If a and b are constants, what is one solution of the equation \((x+a)(x-b)=0?\)
1) \(a = 4\)
2) \(b = 3\)
The OA is D
Statement 1: a = 4
This means the equation is (x + 4)(x - b) = 0
So, x = -4, is one possible solution to the equation.
Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: The b = 3
This means the equation is (x + a)(x - 3) = 0
So, x = 3, is one possible solution to the equation.
Since we can answer the target question with certainty, statement 2 is SUFFICIENT
Answer = D