Last year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees. Each of the 2 owners received 3 times as much as each of their 10 employees. How much did each owner receive from the $48,000 ?
A. $12,000
B. $9,000
C. $6,000
D. $4,000
E. $3,000
Answer: B
Source: Official guide
Last year $48,000 of a certain store's profit was shared by its 2 owners
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Each owner received 3 times as much as each employeeBTGModeratorVI wrote: ↑Sun Sep 27, 2020 7:09 amLast year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees. Each of the 2 owners received 3 times as much as each of their 10 employees. How much did each owner receive from the $48,000 ?
A. $12,000
B. $9,000
C. $6,000
D. $4,000
E. $3,000
Answer: B
Source: Official guide
Let E = the amount (in dollars) that ONE employee received
So, 3E = the amount (in dollars) that ONE owner received
Last year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees.
In other words: 3E + 3E + E + E + E + E + E + E + E + E + E + E = 48,000
Simplify: 16E = 48,000
So, E = 48,000/16
= 3,000
So, each EMPLOYEE received $3000, which means each OWNER received $9000
Answer: B
Cheers,
Brent
GMAT/MBA Expert
- Brent@GMATPrepNow
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- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
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Although I believe it's best to use one variable to solve this question, we can also use two variablesBTGModeratorVI wrote: ↑Sun Sep 27, 2020 7:09 amLast year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees. Each of the 2 owners received 3 times as much as each of their 10 employees. How much did each owner receive from the $48,000 ?
A. $12,000
B. $9,000
C. $6,000
D. $4,000
E. $3,000
Answer: B
Source: Official guide
Let's see how that solution would look.
Let x = the amount (in dollars) that ONE employee received
Let y = the amount (in dollars) that ONE owner received
Each owner received 3 times as much as each employee
So, we can write: y = 3x
Last year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees.
So, the total amount two owners received = y + y = 2y
The total amount 10 employees received = 10x
So, we can write: 10x + 2y = 48,000
At this point, we have the following system of linear equations:
y = 3x
10x + 2y = 48,000
When we solve this system (I'll leave it to you to do this), we get x = 3000 and y = 9000
So, each each OWNER received $9000
Answer: B
Cheers,
Brent