[GMAT math practice question]
How many arrangements of the letters 's', 'u', 'c', 'c', 'e', 's', 's' in a straight line are possible?
A. 60
B. 120
C. 180
D. 240
E. 420
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How many arrangements of the letters ‘s’, ‘u’, ‘câ
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Max@Math Revolution
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The seven letters 's', 'u', 'c', 'c', 'e', 's', 's' include three s's and two c's.
The number of permutations is 7! / (3!*2!) = 420.
Therefore, the answer is E.
Answer: E
The seven letters 's', 'u', 'c', 'c', 'e', 's', 's' include three s's and two c's.
The number of permutations is 7! / (3!*2!) = 420.
Therefore, the answer is E.
Answer: E
Math Revolution
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[Free] Full on-demand course (7 days) - 100 hours of video lessons, 490 lesson topics, and 2,000 questions.
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