GMAT Prep Math zy < xy < 0 |x-z| + |x| = |z|

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Proof_or so I think!

by manjithmanohar » Wed Mar 25, 2009 5:21 am
The basic condition for the equation |x-z| + |x| = |z| to be true is that
|z| > |x|

The inequality zy < xy < 0
further implies that |z| > |x| where the y value could be both +/ - respectively to maintain the inequality. (I hope I don't need to elaborate this part)

So considering the answers:

1. z < x (if it is considered with the inequality both z and x are negative and that y is positive.) so proves |z| > |x|, hence true.
2. y < 0 (when fit into the inequality proves that again |z| > |x|) so true.

Answer most definitely is D.

Please feel free to discuss this! :D

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by Ian Stewart » Wed Mar 25, 2009 7:36 am
I posted a solution to this to another forum, so I'll just paste that here:

_______________

This is one of the strangest questions in GMATPrep, since you don't need either of the statements to answer the question. That's not supposed to happen on a GMAT DS question, which makes me wonder whether there was an error in the question design. In any case, we're given:

zy < xy < 0

Rewrite this as three inequalities:

(1) xy < 0
(2) zy < 0
(3) zy < xy

From (1), we have two possibilities:

(A) x is positive, and y is negative. Then, from (2), z is positive, and from (3), dividing by y and reversing the inequality because y is negative, we have x < z. So it may be that y < 0 < x < z .

(B) x is negative and y is positive. Then, from (2), z is negative, and from (3), dividing by y, we have z < x. So it may be that z < x < 0 < y .

Those are the only two possibilities here. Draw the number line in each case:

(A)

--------y-------0--------x--------z----------

(B)

-z--------x-----0---------y------------------


In either case, we can see that the distance from z to zero is equal to the sum of the distance from x to zero and the distance from x to z. That is, in either case, |z| = |x| + |x - z|. So we don't need any additional information to be sure that the answer to the question is yes - neither of the statements is required here.

I suppose that makes the answer 'D', though it's the only question I know of in any official GMAT material (and I've seen pretty much every question) where the statements aren't needed to answer the question given.
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Re: Proof_or so I think!

by bluementor » Wed Mar 25, 2009 9:10 am
manjithmanohar wrote: 1. z < x (if it is considered with the inequality both z and x are negative and that y is positive.) so proves |z| > |x|, hence true.
2. y < 0 (when fit into the inequality proves that again |z| > |x|) so true.
I thought DS statements should never contradict each other. You are getting y>0 in the first statement, and this clearly contradicts statement 2.

As Ian mentions in his post, this is a strange question.

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Re: Proof_or so I think!

by Ian Stewart » Wed Mar 25, 2009 9:25 am
bluementor wrote:
manjithmanohar wrote: 1. z < x (if it is considered with the inequality both z and x are negative and that y is positive.) so proves |z| > |x|, hence true.
2. y < 0 (when fit into the inequality proves that again |z| > |x|) so true.
I thought DS statements should never contradict each other. You are getting y>0 in the first statement, and this clearly contradicts statement 2.

As Ian mentions in his post, this is a strange question.

-BM-
Nicely spotted - that's a typo in the original post, and in the real version of the question, Statement 2 reads "y > 0". The question is from GMATPrep; there's a screenshot of the question here:

gmatclub.com/forum/t70195-modulus-gmat-prep
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by ghacker » Sun Jun 14, 2009 7:48 am
This is a very simple question



Answer is D

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by rah_pandey » Wed Jun 17, 2009 2:00 am
Ian is right that none of the condition is needed to give the answer to the question. The equality is true under all circumstances

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by r321 » Mon Feb 28, 2011 12:29 pm
Ian Stewart wrote:I posted a solution to this to another forum, so I'll just paste that here:

_______________

This is one of the strangest questions in GMATPrep, since you don't need either of the statements to answer the question. That's not supposed to happen on a GMAT DS question, which makes me wonder whether there was an error in the question design. In any case, we're given:

zy < xy < 0

Rewrite this as three inequalities:

(1) xy < 0
(2) zy < 0
(3) zy < xy

From (1), we have two possibilities:

(A) x is positive, and y is negative. Then, from (2), z is positive, and from (3), dividing by y and reversing the inequality because y is negative, we have x < z. So it may be that y < 0 < x < z .

(B) x is negative and y is positive. Then, from (2), z is negative, and from (3), dividing by y, we have z < x. So it may be that z < x < 0 < y .

Those are the only two possibilities here. Draw the number line in each case:

(A)

--------y-------0--------x--------z----------

(B)

-z--------x-----0---------y------------------


In either case, we can see that the distance from z to zero is equal to the sum of the distance from x to zero and the distance from x to z. That is, in either case, |z| = |x| + |x - z|. So we don't need any additional information to be sure that the answer to the question is yes - neither of the statements is required here.

I suppose that makes the answer 'D', though it's the only question I know of in any official GMAT material (and I've seen pretty much every question) where the statements aren't needed to answer the question given.
I just got this question on my prep test today and spent about 10 minutes after the test trying to figure out why I would need either of the statements to answer the question stem...until, of course, i found this post (and others like it - https://www.manhattangmat.com/forums/pos ... tml#p30742)

Makes me wonder though - if all the gmat prep software questions are retired questions from the official test, doesn't that mean that the official GMAT at one point contained this (clearly flawed) question!

And, I downloaded the prep software only in January '11 - seems like they still haven't realised that this question is flawed..