If the area of square S and the area of circle C are equal, then the ratio of the perimeter of S to the circumference of C is closest to ...
a)7/9
b)8/9
c)9/8
d)4/3
e)2/1
Not sure how to do this.
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Geometry problem
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Area of square and circle is equal
Lets say area is 100
Square - Area = 100 side = 10 and perimeter = 40
Circle - Area = pi*r^2 = 100, radius = 5.6 approx perimeter = 2pir = 31 approx
ratio of 40/32 = 4/3 approx.
Ans D.
Lets say area is 100
Square - Area = 100 side = 10 and perimeter = 40
Circle - Area = pi*r^2 = 100, radius = 5.6 approx perimeter = 2pir = 31 approx
ratio of 40/32 = 4/3 approx.
Ans D.
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s^2 = pi * r^2rwrangler wrote:If the area of square S and the area of circle C are equal, then the ratio of the perimeter of S to the circumference of C is closest to ...
a)7/9
b)8/9
c)9/8
d)4/3
e)2/1
Not sure how to do this.
s/r = sqrt(pi)
So, 4s / (2*pi*r) = 2 / sqrt(pi)
sqrt(pi) = sqrt(3.14) ~ 1.7
So, we know 2/1.7 > 1 and <2> 1.33. Hence, C
