Hi,
Please help in solving.
How to manipulate ?
geometry-Hypotenuse
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- cubicle_bound_misfit
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Cubical this should be a 45 45 90 triangle side being x x x\/2(sq root 2)
so sum is 2x+\/2x = \/2(\/2+1)x = 16(\/2+1)
So x = 8\/2
and hyp = x\/2 = 16
so sum is 2x+\/2x = \/2(\/2+1)x = 16(\/2+1)
So x = 8\/2
and hyp = x\/2 = 16
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Since its a right angled isoceles so two sides are equal and the third one will be the hypotenuse.
So, let the equal side both be equal to a
The hypotenuse will be a*(root 2)
Perimeter = sum of all sides => a+a+ a(root 2) = 16 + 16 (root 2)
2a+(root 2)a = 16+ 16 (root 2)
=> a = 8(root 2)
Could not find the symbol for square root
So, let the equal side both be equal to a
The hypotenuse will be a*(root 2)
Perimeter = sum of all sides => a+a+ a(root 2) = 16 + 16 (root 2)
2a+(root 2)a = 16+ 16 (root 2)
=> a = 8(root 2)
Could not find the symbol for square root
MS
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Since its a right angled isoceles so two sides are equal and the third one will be the hypotenuse.
So, let the equal side both be equal to a
The hypotenuse will be a*(root 2)
Perimeter = sum of all sides => a+a+ a(root 2) = 16 + 16 (root 2)
2a+(root 2)a = 16+ 16 (root 2)
=> a = 8(root 2)
Could not find the symbol for square root
So, let the equal side both be equal to a
The hypotenuse will be a*(root 2)
Perimeter = sum of all sides => a+a+ a(root 2) = 16 + 16 (root 2)
2a+(root 2)a = 16+ 16 (root 2)
=> a = 8(root 2)
Could not find the symbol for square root
MS
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I say 16.
16/square root of 2 = 8 square root of 2
So hyp = 16 + 2 sides
2 sides = 2(8 sqrt 2)
16 square root of 2 + 16
como sey llamaaaaa?
16/square root of 2 = 8 square root of 2
So hyp = 16 + 2 sides
2 sides = 2(8 sqrt 2)
16 square root of 2 + 16
como sey llamaaaaa?