A batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either the blue tin or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin?
(A) 15/2
(B) 9/4
(C) 5/9
(D) 7/5
(E) 9/7
OA: C
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Error in Kaplan 800 - Word Problem # 5
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bml1105
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When reading the explanation in the book it says what we are looking for is as follows:
(# of cookies in green tin)/{(# of cookies in green tin)+(# of cookies in red tin)}
Why would the number of cookies in the green tin be in the denominator? Shouldn't it be the # of cookies in the blue tin + the # of cookies in the red tin, since the question asks "what fraction of the cookies that were placed in the other tins were placed in the green tin"
(# of cookies in green tin)/{(# of cookies in green tin)+(# of cookies in red tin)}
Why would the number of cookies in the green tin be in the denominator? Shouldn't it be the # of cookies in the blue tin + the # of cookies in the red tin, since the question asks "what fraction of the cookies that were placed in the other tins were placed in the green tin"
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Brent@GMATPrepNow
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Let's start with a certain number of cookies that works well with all of the fractions.bml1105 wrote:A batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either the blue tin or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin?
(A) 15/2
(B) 9/4
(C) 5/9
(D) 7/5
(E) 9/7
OA: C
Let's say that there are 36 cookies altogether.
2/3 of all the cookies were placed in either the blue tin or the green tin
So, 24 cookies were placed in either the blue tin or the green tin
The rest were placed in the red tin
So, 12 cookies were placed in the red tin
1/4 of all the cookies were placed in the blue tin
So, 9 cookies were placed in the blue tin
So, the number of cookies that were placed in the green tin = 36 - 12 - 9 = 15
If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other (non blue) tins were placed in the green tin?
There are 27 cookies in the non-blue tins.
15 of them are in the green tin
Fraction = 15/27 = [spoiler]5/9[/spoiler]
Answer: C
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Brent
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Hi bml1105,
Are these answer choices formatted correctly? I agree with Brent's approach (TESTing VALUES works really well on this question), but these answers, as written, imply that the only possible answer is the correct one.
GMAT assassins aren't born, they're made,
Rich
Are these answer choices formatted correctly? I agree with Brent's approach (TESTing VALUES works really well on this question), but these answers, as written, imply that the only possible answer is the correct one.
GMAT assassins aren't born, they're made,
Rich
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theCodeToGMAT
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B/G = 2/3 * C
R = 1/3 * C
B = 1/4 * C
Let Cookies be 60
B/G = 40
R = 20
B = 15
So, G = 25
Fraction: 25/45 = 5/9
R = 1/3 * C
B = 1/4 * C
Let Cookies be 60
B/G = 40
R = 20
B = 15
So, G = 25
Fraction: 25/45 = 5/9
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bml1105
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Rich, I just double checked the book and it is written correctly. It's Kaplan 800 - Arithmetic and Algebra Word Problems #5.
I was reading the question as what fraction of cookies is in green compared to the cookies in blue and red OR (# in green tin)/[(# in red tin) + (# in blue tin)] and wondering why I was getting it wrong.
I was reading the question as what fraction of cookies is in green compared to the cookies in blue and red OR (# in green tin)/[(# in red tin) + (# in blue tin)] and wondering why I was getting it wrong.
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GMATGuruNY
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Let the total number of cookies = the LCM of the two denominators in the prompt = 12bml1105 wrote: ↑Thu May 29, 2014 4:49 pmA batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either the blue tin or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin?
(A) 15/2
(B) 9/4
(C) 5/9
(D) 7/5
(E) 9/7
Since 2/3 of the cookies are placed in the blue or green tin, B+G = 2/3* 12 = 8
Since 1/4 of the cookies are placed in the blue tin, B = 1/4 * 12 = 3
What fraction of the cookies that were placed in the other tins were placed in the green tin?
other tins = total - B = 12-3 = 9
G = (B+G) - B = 8-3 = 5
green/other = 5/9
The correct answer is C.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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