Hi,
Please help in solving.
My idea was that 120/360 * 2*pi*r = 24.
Let me know where I am wrong.
Question-Arc for Equilateral
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- cubicle_bound_misfit
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actually it should be 240/360 (of circle perimeter) = 24. Since each of the angles of equilateral are 60 degrees. then angle ABC = 240 degrees
perimeter = 36
2 * pi * r = 36 gives D = 11 (approx)
perimeter = 36
2 * pi * r = 36 gives D = 11 (approx)
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Measure of Arc AC-120 degrees
Measure of Arc ABC-360-120=240 degrees
C=Pi*d
Pi*d*2/3=24
24*3/2=Pi*d
36/pi=d
36/3.14~11
Measure of Arc ABC-360-120=240 degrees
C=Pi*d
Pi*d*2/3=24
24*3/2=Pi*d
36/pi=d
36/3.14~11
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Given ABC arc = 24
=>One arc following AB will be 12
Given angle at circumference is 60 angle at centre will be 120
So the circumference = arc of 360 = 3*arc corresponding 120 = 3*12=36
=>II.D = 36 or D = 36/3.14 = 11
=>One arc following AB will be 12
Given angle at circumference is 60 angle at centre will be 120
So the circumference = arc of 360 = 3*arc corresponding 120 = 3*12=36
=>II.D = 36 or D = 36/3.14 = 11
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It is the major arc bcoz it says ABC so you have to from A to B to C... otherwise it would have been ACB, for it to be the minor arc
MS
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