the question is
If X and Y are integers, does x = y?
1) xy = y2 (2 here is square)
2) x2 = y2 (2 here is square)
I think the answer should be B but OA is D.
(1) is insufficient as y can be 0 and the eqn will not satisfy
DS question
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If X and Y are integers, does x = y?
1) xy = y2 (2 here is square)
2) x2 = y2 (2 here is square)
xy = y^2
x=y
Statement A is sufficient
x^2 = y^2
If x = (-5)^2 and y =5^2
Then x and y are not equal
If x = 5 and y = 5
Then x=y
Statement B is insufficient
1) xy = y2 (2 here is square)
2) x2 = y2 (2 here is square)
xy = y^2
x=y
Statement A is sufficient
x^2 = y^2
If x = (-5)^2 and y =5^2
Then x and y are not equal
If x = 5 and y = 5
Then x=y
Statement B is insufficient
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I'm not too convinced (1) is sufficient.gviren wrote:the question is
If X and Y are integers, does x = y?
1) xy = y2 (2 here is square)
2) x2 = y2 (2 here is square)
I think the answer should be B but OA is D.
(1) is insufficient as y can be 0 and the eqn will not satisfy
1 - insufficient
xy = y^2
y(x-y) = 0
(please note that you cannot cancel out y from both sides
without knowing that y != 0)
So, either y = 0 or x = y. 0 is an integer, so we cannot rule out y=0
2 - insufficient as well.
Take x = y = 5. Ofcourse x = y
Take x = 5 and y = -5. x is not equal to y
Taking both together, we know x = y.
I'd vote for C
Can someone please correct me if there's something amiss in my
reasoning.