For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year?
1 Company R's revenue target for December of next year is 310,000
2 Company R's revenue target for september of next year is 30,000 greater than its revenue target for June of next year.
OA C
DS question
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C because
St 1
1 Company R's revenue target for December of next year is 310,000
Don't know anything about x
2 Company R's revenue target for september of next year is 30,000 greater than its revenue target for June of next year.
Don't know the original number . x is 30k
Combined
December is 310,000 and x is 30,000 so march (3 months from december) is 310,000+ 3*30000 = 400,000
St 1
1 Company R's revenue target for December of next year is 310,000
Don't know anything about x
2 Company R's revenue target for september of next year is 30,000 greater than its revenue target for June of next year.
Don't know the original number . x is 30k
Combined
December is 310,000 and x is 30,000 so march (3 months from december) is 310,000+ 3*30000 = 400,000
- gmat740
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I. March + 8x = Dec
March + 8x = 310k
Insuff
(II) Sept-June = 30k
but Sept - June = 3x
so 3x = 30k
x =10
But we have to find for March
Which can be calculated with (I)
So Both (I) and (II) are required
Hope this helps
Karan
March + 8x = 310k
Insuff
(II) Sept-June = 30k
but Sept - June = 3x
so 3x = 30k
x =10
But we have to find for March
Which can be calculated with (I)
So Both (I) and (II) are required
Hope this helps
Karan
- cubicle_bound_misfit
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Why we can not assume that say as next year started for january so beginiing was 'J' $ and after that a series with CD X. Anything wrong with that approach? stil getting answer C as we have to solve for two varibales J and x
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