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chuongbill
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I also agree with the answer is 70, but If 56 is the official answer, I think it might be wrong.
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Patrick_GMATFix
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dferm you unfortunately misread the answer.
This is a straightforward combinatorics. We have 5 women and 7 men. From these 3 women and 1 man will be selected. There are 10 ways to pick 3 women from 5. There are 7 ways to pick 1 man from 7. To do both, there are 10*7=70 ways. The OA to this is definitely D.
This question, a full explanation and step by step video solution are at GMATPrep Question 1509. To take drills with similar questions, set topic='Combinatorics' and difficulty='600-700 & 700+' in the Drill Generator
-Patrick
This is a straightforward combinatorics. We have 5 women and 7 men. From these 3 women and 1 man will be selected. There are 10 ways to pick 3 women from 5. There are 7 ways to pick 1 man from 7. To do both, there are 10*7=70 ways. The OA to this is definitely D.
This question, a full explanation and step by step video solution are at GMATPrep Question 1509. To take drills with similar questions, set topic='Combinatorics' and difficulty='600-700 & 700+' in the Drill Generator
-Patrick
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