Geometry-Triangle twice as bigger as the other one

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Can someone please help me. OA is s SQ2.

Thanks
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by aatech » Mon May 26, 2008 6:42 pm
Suppose the height of smaller triangle is h and height of bigger triangle is H... From the figure we can say that the triangles are congruent...means

s/S = h/H ----(1)

From q we know (s*h/2)*2 = S*H/2 ---- (2)

Solve 1 and 2 to get s^2 = S^2/2 so S = root2*s ANS

OA?

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by khurram » Mon May 26, 2008 9:01 pm
Ans is square root 2*s. hence C.

Thanks
Khurram