I want to be able to solve this problem with Arithmetic and by plugging numbers.
a number line, a < b < c < d. The distance from a to b is of the distance from b to d. The distance from a to c is 3 times the distance from c to d. What is the value of ?
a) 3/20
b) 1/5
c) 4/15
d) 7/20
e) 3/5
Distance problem
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I think the correct problem read like this:Taniuca wrote:a number line, a < b < c < d. The distance from a to b is of the distance from b to d. The distance from a to c is 3 times the distance from c to d. What is the value of ?
On a number line, a<b<c<d. The distance from a to b is 1/4 of the distance from b to d. The distance from a to c is 3 times the distance from c to d. What is the value of (b-a)/(c-a)?
Choose the values of a, b, c and d conveniently but in accordance with the given constraints.
Set a = 0 and b = 1
As the distance from a to b is 1/4 of the distance from b to d
=> (b - a) = (d - b)/4
=> (1 - 0) = (d - 1)/4
=> d = 4 + 1 = 5
As the distance from a to c is 3 times the distance from c to d
=> (c - a) = 3(d - c)
=> (c - 0) = 3(5 - c)
=> c + 3c = 15
=> c = 15/4
Thus, (b - a)/(c - a) = b/c = 4/15
The correct answer is C.
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)