800guy wrote:i'll post the OA when a few people have responded...

**A bag contains 3 red, 4 black and 2 white balls. What is the probability of drawing a red and a white ball in two successive draws, each ball being put back after it is drawn?**

(A) 2/27

(B) 1/9

(C) 1/3

(D) 4/27

(E) 2/9

(probability of a white and a red, whatever the order):

Hence

P(take a red and then a white) = 3/9 * 2/9 = 2/27

P(take a white and then a red) = 2/9 * 3/9 = 2/27

=> Total P =4/27, answer D.

IMHO, not a very difficult probability problem... I've seen much worse