1. Is the average (arithmetic mean) of 5 different positive integers atleast 30?
a. Each of the integer is a multiple of 10
b. The sum of the integer is 160
2. IxI = Y - Z ?
a. X + Y = Z
b. X < 0
3. Warehouse Q's revenue from the sale of sofas was what percent greater this year than it was last year?
a. Warehouse W sold 10 percent more sofas this year than it did last year
b. Warehouse W's selling price per sofa was $30 greater this year than it was last year
4. Circle C and line k lie in the xy-plane. If circle C is centered at the origin and has radius 1, does line k intersect c?
a. The x intercept of line k is greater than 1
b. The slope of line k is -1/10
Data Sufficiency
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- force5
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IMO D1. Is the average (arithmetic mean) of 5 different positive integers atleast 30?
a. Each of the integer is a multiple of 10
b. The sum of the integer is 160
stmnt A- (sufficient)5 positive integers multiple of 10 will always have average more than 30 ( remember 1st positive integer will be 10)
stment2- (sufficient) if sum is 160 then average 160/5 will always be greater than 30
hope it helps
- force5
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3. Warehouse Q's revenue from the sale of sofas was what percent greater this year than it was last year?
a. Warehouse W sold 10 percent more sofas this year than it did last year
b. Warehouse W's selling price per sofa was $30 greater this year than it was last year
IMO E
we need to find increase/last year's profit
(1) (insuff) if last year is x then this year is 1.1x
required percent is 0.1/x
(2) (insuff) selling price last year y, this year y+30
reqd percent 30/y moreover no info about how many sofa's
combining (insuff)
still 2 variables.
hope it helps
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- Anurag@Gurome
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Statement 1: Minimum possible values of the integers are 10, 20, 30, 40, and 50. Hence minimum possible average is 30.Tagne wrote:1. Is the average (arithmetic mean) of 5 different positive integers atleast 30?
a. Each of the integer is a multiple of 10
b. The sum of the integer is 160
Sufficient
Statement 2: Sum of the integers = 160 and number of integers = 5
Hence, average = 160/5 = 32
Sufficient
The correct answer is D.
Last edited by Anurag@Gurome on Sat Mar 19, 2011 2:32 am, edited 1 time in total.
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- force5
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Good question4. Circle C and line k lie in the xy-plane. If circle C is centered at the origin and has radius 1, does line k intersect c?
a. The x intercept of line k is greater than 1
b. The slope of line k is -1/10
IMO- E
lets start with stmnt 2
insuff- info means slope is -ve but no other info about the line. line can be anywhere.
stmnt1- insuff
we dont know what is the slope of the line
combining ( still insuff)
although it seems that C will give the answer. however there can be two scenarios. (1) the point according to stmnt1 lies close to x=1 ( though will still be greater than 1) ... in this case the line will intersect the circle. (2) consider that the point lies too far away on x axis... say x= 100000000000000 then this line will not intersect the circle.
Hope it helps..
- force5
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hi Anurag i think the answer to this question should be D. the integers have to be +ve. Zero is not a positive integer. hence the first integer here will have to be 10...Statement 1: Let's assume following set of integers
1. {0, 10, 20, 30, 40} --> Average = 20
2. {10, 20, 30, 40, 50} --> Average = 30
Not sufficient
Statement 2: Sum of the integers = 160 and number of integers = 5
Hence, average = 160/5 = 32
Sufficient
The correct answer is B.
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Statement 1: x + y = z => x = (z - y)Tagne wrote:2. IxI = Y - Z ?
a. X + Y = Z
b. X < 0
Now, we have two possible scenarios
- 1. x ≥ 0 => |x| = x = (z - y) --> Answers the question in NO
2. x < 0 => |x| = -x = (y - z) --> Answers the question in YES
Statement 2: No information about y and z --> Not sufficient
1 & 2 Together: Now we know x is negative.
Hence, |x| = -x = (y - z)
Sufficient
The correct answer is C.
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- force5
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Guys please correct.. the answer should be C. i did make a mistake.MO- A
stmnt 1 - ( sufficient) x+y=z
then x = z-y ( when x positive)
x= y-z ( when x negative)
stmnt2- ( insufficient)
thanks
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Thanks for the correction.force5 wrote:hi Anurag i think the answer to this question should be D. the integers have to be +ve. Zero is not a positive integer. hence the first integer here will have to be 10...
Edited the reply.
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