Consider two integers: an original two digits integer and

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Consider two integers: an original two digits integer and the integer formed by reversing the digits of this original integer. If the bigger of these two integers is divided by the other integer, what could be the maximum remainder?
1) 9
2)27
3)36
4)45
5) 54
Last edited by mensanumber on Tue Apr 17, 2018 1:29 pm, edited 1 time in total.

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by [email protected] » Tue Apr 17, 2018 5:51 am
mensanumber wrote:If a two digit integer is divided by an integer formed by reversing its digits, what could be the maximum remainder?
1) 9
2)27
3)36
4)45
5) 54
How about 89 divided by 98?
89 divided by 98 equals 0 with remainder 89
I don't see 89 as an answer choice.
Am I missing something?

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Brent
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by mensanumber » Tue Apr 17, 2018 1:31 pm
[email protected] wrote:
mensanumber wrote:If a two digit integer is divided by an integer formed by reversing its digits, what could be the maximum remainder?
1) 9
2)27
3)36
4)45
5) 54
How about 89 divided by 98?
89 divided by 98 equals 0 with remainder 89
I don't see 89 as an answer choice.
Am I missing something?

Cheers,
Brent
Sorry, just edited my question.

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by [email protected] » Thu Apr 19, 2018 4:37 pm
mensanumber wrote:Consider two integers: an original two digits integer and the integer formed by reversing the digits of this original integer. If the bigger of these two integers is divided by the other integer, what could be the maximum remainder?
1) 9
2)27
3)36
4)45
5) 54
The largest possible remainder is when we divide 94/49 = 1 remainder 45.

Answer: D

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