Combinations

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Combinations

by swerve » Sun Dec 29, 2024 10:44 am

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Your Answer

A

B

C

D

E

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How many different \(11-\)letter arrangements are possible with the letters \(aabbbbccccc?\)

A. \(11\)
B. \(45\)
C. \(90\)
D. \(6930\)
E. \(11!\)

The OA is D

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Re: Combinations

by shawlless » Wed Jan 01, 2025 8:59 pm
Explain?

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Re: Combinations

by SanjuSimpleson » Thu Jan 16, 2025 2:55 am
$$\frac{11!}{2!4!5!}$$

$$\frac{11!}{2!4!5!}\ =\ 6930$$