Challenge question: N is a 2-digit integer. When the di

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N is a 2-digit integer. When the digits of N are reversed, the resulting number is M. If -1 < N - M < 15, what is the value of N?

(1) The sum of N's digits is 15.
(2) The tens digit of N is 1 greater its units digit

Answer: A
Difficulty level: 650 - 700
Source: www.gmatprepnow.com

*I'll post a full solution in 2 days
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by arosman » Wed Jun 20, 2018 10:36 am

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Let's say the digits are represented as "a" and "b"

N = ab
M = ba

Algebraically this translates to:

N = 10a + b
M = 10b + a

Statement 1)
I just did this by testing numbers
Possible combos are:
N = 87, M = 78 ---> N - M = 0 ----> WORKS
N = 78, M = 87 ----> N - M = -9 ---> DOESN'T WORK
N = 96, M = 69 -----> N - M = 27 ----> DOESN'T WORK
N = 69, M = 96 -----> N - M = -27 ----> DOESN'T WORK

N must be 87 ----> SUFFICIENT

Statement 2)
This tells us that a = b +1

Possible combos:
N = 21, M = 12 ------> N - M = 9 ------> WORKS
N = 32, M = 23 -----> N - M = 9 --------> WORKS

Since N can be 32 or 21 this is INSUFFICIENT

ANSWER: A
Adam Rosman, MD
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by Brent@GMATPrepNow » Wed Jun 20, 2018 3:30 pm

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Brent@GMATPrepNow wrote:N is a 2-digit integer. When the digits of N are reversed, the resulting number is M. If -1 < N - M < 15, what is the value of N?

(1) The sum of N's digits is 15.
(2) The tens digit of N is 1 greater its units digit

Answer: A
Difficulty level: 650 - 700
Source: www.gmatprepnow.com

*I'll post a full solution in 2 days
Target question: What is the value of N?

Given: N is a 2-digit integer. When the digits of N are reversed, the resulting number is M. -1 < N - M < 15
Let x = the tens digit of N
Let y = the units digit of N
So, the VALUE of N = 10x + y

When we reverse the digits, we get M = yx
So, the VALUE of M = 10y + x

So, N - M = (10x + y) - (10y + x)
= 9x - 9y
= 9(x - y)
In other words, N - M = some multiple of 9
We're told that -1 < N - M < 15
There are exactly two multiples of 9 between -1 and 15. They are 0 and 9.
So EITHER N - M = 0 OR N - M = 9

Let's examine each case:
CASE A: If N - M = 0, then 9(x - y) = 0, which means x - y = 0, which means x = y
CASE B: If N - M = 9, then 9(x - y) = 9, which means x - y = 1, which means x = y + 1

Statement 1: The sum of N's digits is 15
In other words, x + y = 15
If x and y are INTEGERS, and if x + y = 15, then x cannot equal y
This rules out CASE A, which means CASE B must be true. That is, x = y + 1
We now have two equations:
x + y = 15
x = y + 1

Since we COULD solve this system for x and y, we COULD determine the value of N
Since we COULD answer the target question with certainty, statement 1 is SUFFICIENT

Aside: If we solve the system, we get: x = 7 and y = 8
So, N = 78

Statement 2: The tens digit of N is 1 greater its units digit
In other words, x = y + 1
This means CASE B is true (i.e., x = y + 1 )
Given this, there are many values of N that statement 2.
For example, it could be the case that N = 21 or N = 32 or N = 43 or N = 54 etc.
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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